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Given the area of ABC=7.52m^2. Find a to the nearest hundredth meter when m<B=40 degrees and c=6m

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  1. If h is the altitude from C to AB, we have

    1/2 * ch = 3h = 7.52
    So, h = 2.507

    Now h/a = sin 40°
    a = 2.507/0.642 = 3.90

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    posted by Steve

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