# HELP!!!

Given the area of ABC=7.52m^2. Find a to the nearest hundredth meter when m<B=40 degrees and c=6m

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1. If h is the altitude from C to AB, we have

1/2 * ch = 3h = 7.52
So, h = 2.507

Now h/a = sin 40°
a = 2.507/0.642 = 3.90

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posted by Steve

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