# physics

An object dropped from a cliff falls with a constant acceleration of 10m/s2. Find its speed 2s after it was dropped?
Solution:Given ,accelaration =10m/s
time=2s
speed=?
therfore,speed=distance travelled\total time taken
s=10\2=5(ans) . is it ok.

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1. Not really.
For an object which accelerates from rest, the variation of speed with time is given by:
final velocity=initial velocity + acceleration * time
= 0 + 10 m/s² * 2 s
=20 m/s
(note how the units cancel to give m/s)

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2. We will apply v=u+at . 0+2×10= 20m/s

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posted by Drishti

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