NCCU

11. What mass of sodium benzoate should be added to 160.0mL of a 0.17M benzoic acid solution in order to obtain a buffer with a pH of 4.30?

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asked by Bri
  1. I don't think we have any experts in the school subject of NCCU.

  2. millimols benzoic acid = mL x M = about 27 but that's an estimate and you should redo the math.
    Then pH = pKa + log (base)/(acid)
    4.30 = pKa benzoic acid + log benzoate/27
    Look up the value of pKa for benzoic acid, substitute, solve for base. That will be millimols sodium benzoate needed. Change to mols, then mols = g/molar mass. You know molar mass and mols, solve for grams.

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  3. I would have answered this much quicker if you had typed in the subject instead of something obscure like NCCU.

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