An antitank weapons fires a 3.5 rocket, which acquires a speed of 70 m/s after traveling 90cm down a launching tube. Find the net force during lonch?
I guess maybe you mean 3.5 kg ???
Force = change in momentum / change in time
average speed = (70+0)/2 = 35 m/s
so
time = .90 /35 = .0257 seconds
F = 3.5 * 70 / .0257
= 9528 N
To find the net force during launch, we need to use Newton's second law of motion, which states that the net force acting on an object is equal to its mass multiplied by its acceleration.
First, let's convert the distance traveled down the launching tube from centimeters to meters. Since 1 meter is equal to 100 centimeters, 90 cm is equal to 0.9 meters.
Next, we need to determine the acceleration of the rocket during its launch. We can use the following equation to find the acceleration:
v^2 = u^2 + 2as
where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance traveled.
Rearranging the equation, we get:
a = (v^2 - u^2) / (2s)
Plugging in the given values, we have:
a = (70^2 - 0^2) / (2 * 0.9)
a = 4900 / 1.8
a ≈ 2722.22 m/s^2
Now, we can calculate the net force. We have the final velocity of the rocket, but we need to determine the mass of the rocket first in order to compute the net force. Unfortunately, the mass of the rocket is not provided in the question.
If you have the mass of the rocket, you can calculate the net force using the formula:
Net force = mass * acceleration
However, without the mass value, it is not possible to determine the net force during launch.