hydrogen selenide can be prepaired by reacting aluminium selinide with water the other product being solid aluminium hydoxide AL(OH)3,write a balanced chemical equasion for the reaction of aluminium selenide with water including the phisical states of the reactents please i need help???
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Of course! Allow me to help you write the balanced chemical equation for the reaction of aluminum selenide (Al2Se3) with water (H2O):
Al2Se3 + 6 H2O → 3 H2Se + 2 Al(OH)3
In this reaction, aluminum selenide (Al2Se3) reacts with water (H2O) to produce hydrogen selenide (H2Se) and solid aluminum hydroxide (Al(OH)3).
To balance the equation, you need to ensure that the same number of atoms of each element appears on both sides of the equation. Let's go through the process step by step:
1. Start with the aluminum atoms. Since there are two aluminum atoms on the left side (Al2Se3) and only two aluminum atoms on the right side (2 Al(OH)3), this is already balanced.
2. Next, balance the selenium atoms. There are three selenium atoms on the left side (Al2Se3) and one selenium atom on the right side (H2Se). To balance this, multiply H2Se by three: 3 H2Se.
3. Now, let's balance the hydrogen atoms. There are twelve hydrogen atoms on the right side (3 H2Se + 6 H2O), so we need to balance this on the left side. Multiply H2O by six: 6 H2O.
Now, the equation is balanced, and the physical states of each reactant and product can be added:
Al2Se3 (s) + 6 H2O (l) → 3 H2Se (g) + 2 Al(OH)3 (s)
In this equation, "(s)" represents a solid, "(l)" represents a liquid, and "(g)" represents a gas.