calculate the percentage by mass of oxygen in trioxonitrate(v) acid
thank pls i really need the answer
H=1×1
N=14×1
O=3×16
1+14+48=63
%mass of oxygen=16÷63×100=25.39
~25.4%
http://www.jiskha.com/display.cgi?id=1402851831
To calculate the percentage by mass of oxygen in trioxonitrate(V) acid, we first need to know the chemical formula of the acid, which in this case is HNO3.
The formula HNO3 indicates that there is one atom of hydrogen (H), one atom of nitrogen (N), and three atoms of oxygen (O) in each molecule of trioxonitrate(V) acid.
To find the percentage by mass of oxygen, we need to determine the molar mass of oxygen in the compound and divide it by the molar mass of the whole compound, then multiply by 100.
Here's how you calculate it:
Step 1: Find the molar mass of oxygen (O). The molar mass of oxygen is 16.00 g/mol.
Step 2: Find the molar mass of the whole compound HNO3. The molar mass of hydrogen (H) is 1.01 g/mol, the molar mass of nitrogen (N) is 14.01 g/mol, and the molar mass of three oxygen atoms (O) is 3 x 16.00 g/mol = 48.00 g/mol.
So, the molar mass of HNO3 is 1.01 g/mol (H) + 14.01 g/mol (N) + 48.00 g/mol (3O) = 63.02 g/mol.
Step 3: Calculate the percentage by mass of oxygen:
Percentage by mass of oxygen = (Molar mass of oxygen / Molar mass of HNO3) x 100
Percentage by mass of oxygen = (16.00 g/mol / 63.02 g/mol) x 100 ≈ 25.4%
Therefore, the percentage by mass of oxygen in trioxonitrate(V) acid (HNO3) is approximately 25.4%.