Divide.
(25x^2 - 40x + 18) div. (5x - 3)
5x - 5 - 3/5x - 3
5x - 8 - 18/5x - 3
5x - 5 + 3/5x - 3
5x - 14
~~~~~~~~~~~~~~~~~~~~~
7x- 14
-------
x - 2
x
7; where x =/ 7
7; where x =/ 2
0
7(x-2)or 7
Damon please
did the first one already
http://www.jiskha.com/display.cgi?id=1402703533#1402703533.1402705078
I really appreciate people like you Damon. People who take their time to helo others ;) You are very kind to do things like this, and i wish I could repay you for helping me ;)
From,
This Girl,
BallaWitSwag,
Ms. Cavill
Kirem (later)
and Nonoisballin
(I have used all those user names, but my most common is This Girl
OH! haha I was writing something sorry didn't see it thanks!
7(x-2) /(x-2) = 7 * 1 = 7
but x may not be 2 or the original denominator would be zero
The first one is C right?
So is the answer for the second one 0?
wait no, it is B, 7; where x =/ 7?
7 where x not equal to 2
(x=2 is not in the domain, function undefined there)
So C again?
and could ask one last question?
I guess C
which is
7; where x =/ 2
assuming that x=/2 means not when x = 2
okay sweet thank you SO MUCH! You should be a teacher man, you would be an EXCELLENT ONE!!
Could I ask you one more question please?
LOL, many years ago.
haha here's my last question
Suppose that y varies inversely with x and that y = 4 when x = 6. What is an equation for the inverse varition?
y = 6/4x
y = 24/x
y = 2/3x
y = x/24
y = k/x
4 = k/6
k = 24
so
y = 24/x
Just do what it says :)