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derivative of (x^3/6)+(1/2x)? i got (x^2/2)(1/2x^2) is that correct? and then wut is the (F'(x))2?...meaning the derivative squred? if you meant (1/2)x^2  1/(2x^2) you are correct I don't think they are looking for the square of
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R=M^2(c/2m/3) dR/dM=CMM^2 I found the derivative. Now how would I find the vale of M that maximize the derivative dR/dM? set it to zero, and solve for m. You get two solutions. Use the second derivative to see which one is the
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Also I would like to know how to set this problem up in finding the answer: Find the second derivative. y= sqrt(3x+4) Thanks, P.S. I tried taking 3x+4 and squaring it to the 1/2. I thought that might've been the same, then I took
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Any help would be much appreciated with the steps involved in each problem given. Thank you. 1) Find derivative if y =cot x + sin x 2) Find derivative if y = (3x+5)^8 3) Find derivative if y = x csc x 4) Find derivative if y = x
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Any help would be much appreciated with the steps involved in each problem given. Thank you. 1) Find derivative if y =cot x + sin x 2) Find derivative if y = (3x+5)^8 3) Find derivative if y = x csc x 4) Find derivative if y = x
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Any help would be much appreciated with the steps involved in each problem given. Thank you. 1) Find derivative if y =cot x + sin x 2) Find derivative if y = (3x+5)^8 3) Find derivative if y = x csc x 4) Find derivative if y = x
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Find the first and second derivative  simplify your answer. y=x/4x+1 I solved the first derivative and got 1/(4x+1)^2 Not sure if I did the first derivative right and not sure how to do the second derivative.
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Calculus> bobpursley
How do you get m=0? from taking the second derivative? does c=1? Can you check my work on how I get the derivative of R=M^2(c/2m/3) NEXT R=1/2(CM^2)1/3(M^3) NEXT dR/dM=CMM^2. I checked in the back, and that was the answer for
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if f(t)=sqrt(4t+1) find f''(2) I got the first derivative to be: 1/2(4t1)^1/2 * 4t^3 and i'm trying to figure out if i need the product rule again to find the second derivative 1t^3(4t1)^3/2 * 4t^3 The answer if 4/27 and I'm
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