8. Each of two urns contains green balls and red balls. Urn one contains 8 green balls and 12 red balls. Urn two contains 5 green balls and 8 red balls. If a ball is drawn from each urn, what is P(red and red)?
A. 79/65
B. 24/65
C. 20/33******?
D. 2/13
oops i mean A
Strike 2
prob (red from 1st then red from 2nd)
= (12/20)(8/13)
= 24/65
haha sorry and thank you i had figured it out but couldn't guess 2 times :)
To find the probability of drawing a red ball from each urn (P(red and red)), you first need to calculate the probabilities of drawing a red ball from each urn separately, and then multiply those probabilities together.
Let's start with urn one:
Urn one contains a total of 8 + 12 = 20 balls.
The probability of drawing a red ball from urn one is given by the ratio of the number of red balls to the total number of balls in the urn:
P(red in urn one) = 12/20
Now let's move on to urn two:
Urn two contains a total of 5 + 8 = 13 balls.
The probability of drawing a red ball from urn two is given by the ratio of the number of red balls to the total number of balls in the urn:
P(red in urn two) = 8/13
To find the probability of drawing a red ball from each urn, we multiply the probabilities together:
P(red and red) = P(red in urn one) * P(red in urn two) = (12/20) * (8/13)
Simplifying the fraction gives:
P(red and red) = (3/5) * (8/13) = 24/65
Therefore, the correct answer is B. 24/65