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Finding three geometrically numbers knowing that their sum is greater than 78 and 30 units exceeds the sum of the other two.

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asked by Victor
  1. strange wording ....

    " Finding three geometrically numbers"
    I assume you have 3 numbers in a geometric sequence.
    "30 units exceeds the sum of the other two"
    ...... which "other two" , the first two, the last two , or the middle two ?

    the three numbers are:
    a, ar, and ar^2
    a + ar + ar^2 > 78

    I will assume that 30 exceeds the sum of the first two
    30 > a + ar
    a(1+r) < 30 and a(1+r + r^2) > 78

    I will continue once you clarify your question.

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    posted by Reiny

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