what is the pH solution in which 15 mL of 0.10 M NaOH has been added to 25 mL of 0.10 M HCl

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  1. HCl + NaOH ==> NaCl + H2O
    millimols NaOH = 15 x 0.1 = 1.5
    mmols HCl = 25 x 0.1 = 2.5
    Excess HCl = 2.5-1.5 = 1
    (HCl) = (H^+) = 1 mmol/40 mL = ?
    Convert to pH.

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  2. Did you get a definitive answer to the SO2/O2/SO3 question?

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