Algebra 1--Please, help me!

1. What are the x- and y-intercepts of the line described by 6x - 2y = 4?

a. x-intercept: 2/3; y-intercept: 2
b. x-intercept: -2/3; y-intercept: 2
c. x-intercept: 2/3; y-intercept: -2
d. x-intercept: -2; y-intercept: 2/3

My answer: ?

2. Which expression is equivalent to 3m^2n/5m x 20mn/n^6?

a. 12m^2/n^4
b. 12m^3/n^3
c. 12m^2n^3
d. 12m/n

My answer: a?

3. Simplify 3/x + 3/5x.

a. 1/x
b. 18/10x
c. 18/5x
d. 1/2x

My answer: ?

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  1. 1. for the x-intercept let y = 0 ---> x = 2/3
    for the y-intercept , let x = 0 ---> y = -2

    2. (3m^2 n)/(5m)(20mn/n^6)
    = (3mn/5)(20m/n^5)
    = 12m^2/n^4 ------> a)

    3.
    3/x + 3/(5x)
    LCD = 5x
    = 15/(5x( + 3/(5x)
    = 18/(5x)-----> c)

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    posted by Reiny

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