# math

What is the period, in seconds, of a simple pendulum of length 3 meters?

Use the gravitational constant g = 9.8 m/s2 and round your answer to two decimal places

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1. surely you have the formula for the period of a pendulum of length L (and small amplitude):

T = 2π √(L/g)

Now just plug in your numbers.

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posted by Steve

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posted by D man
3. the guy up top stupid the answer is wrong

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4. D man is correct, it is 3.48.

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posted by Jay
5. 3.48 just like what D man said

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posted by Vic
6. 4.49

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