math

What is the period, in seconds, of a simple pendulum of length 3 meters?

Use the gravitational constant g = 9.8 m/s2 and round your answer to two decimal places

Please help! A step by step would with the answer would be helpful!

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asked by Katie
  1. surely you have the formula for the period of a pendulum of length L (and small amplitude):

    T = 2π √(L/g)

    Now just plug in your numbers.

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    posted by Steve
  2. the answer is 3.48

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    posted by D man
  3. the guy up top stupid the answer is wrong

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  4. D man is correct, it is 3.48.

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    posted by Jay
  5. 3.48 just like what D man said

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    posted by Vic
  6. 4.49

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    2. 👎 5

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