# Chemistry

A butane lighter had a mass of 24.643 grams before lighting and a mass of 24.592 grams after. How many mL of CO2 were produced? Assume STP.

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1. 2C4H10 + 13O2 ==> 8CO2 + 10H2O

24.643 initial mass
-24.592 after using
--------
00.051g mass butane used.

mols butane = grams/molar mass = estimated 0.00088 but you need to get a more accurate figures.
Using the coefficients in the balanced equation, convert mols butane to mols CO2. That's estimated 0.00088 x (8 mols CO2/2 mols C4H10) = ?
Then use PV = nRT and solve for L; convert to mL.

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posted by DrBob222

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