Chemistry

A butane lighter had a mass of 24.643 grams before lighting and a mass of 24.592 grams after. How many mL of CO2 were produced? Assume STP.

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asked by Heidi
  1. 2C4H10 + 13O2 ==> 8CO2 + 10H2O

    24.643 initial mass
    -24.592 after using
    --------
    00.051g mass butane used.

    mols butane = grams/molar mass = estimated 0.00088 but you need to get a more accurate figures.
    Using the coefficients in the balanced equation, convert mols butane to mols CO2. That's estimated 0.00088 x (8 mols CO2/2 mols C4H10) = ?
    Then use PV = nRT and solve for L; convert to mL.

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    posted by DrBob222

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