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A uniform disk with radius 0.320m and mass 28.0kg rotates in a horizontal plane on a frictionless vertical axle that passes through the center of the disk. The angle through which the disk has turned varies with time according to è(t)= (1.20rad/s)t + (8.70rad/s^2)t^2

my solution:
w(t) = 1.2 + 17.4t
a = (17.4)*(0.32) = 5.568 rad/s2
is my answer CORRECT ??

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asked by Mona
  1. Update ==>

    theta (t) = (1.20rad/s)t + (8.70rad/s^2)t^2

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    posted by Mona

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