physics

A child drops a ball from a height of 10 m. Assume its acceleration increases uniformly at the rate of 10m/s2. find the velocity with which the ball strikes the ground. Find the time taken to the ball reach the ground.

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  1. V^2 = Vo^2 + 2g*h = 0 + 20*10 = 200
    V = 14.14 m/s.

    0.5g*t^2 = 10 m.
    5t^2 = 10
    t^2 = 2
    t = 1.414 s.

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    posted by Henry

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