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calculate the mass of Cuso4.5H2O required to prepare 500 cm3 of a 0.400 m/dm-3 solution

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asked by alice
  1. Assuming you meant 0.400g/dm^3, that translates to 0.0004 g/cm^3

    So, 500cm^3 of that means 0.2 g

    Or, in one step, that's

    500 cm^3 * (1dm/10cm)^3 * 0.4 g/dm^3

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    posted by Steve
  2. I think 0.400 m/dm3 meant 0.400 mols/dm3 = 0.400 M.

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    posted by DrBob222

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