Numer Theory

1+2+3+...+n=(1+n)+(2+(n-1))+(3+(n-2))+...
=(1+n)+(1+n)+(1+n)+...

How many copies of n+1 are in there in the second line?
with n=6 and n=7

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asked by Tiffany
  1. Since the n numbers are divided up in pairs, I'd say n/2 copies.

    Hence the formula for the sum: n(n+1)/2

    Technically, that's [n+1]/2 where [] is the greatest-integer function.

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    posted by Steve

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