math

the sum of 11terms of A.P is 891.find the 28th and 45th terms if the common difference is 45

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asked by emi
  1. If we add up terms n through n+10, then we get

    (n+10)/2 (2a + (n+9)45) - (n-1)/2 (2a+(n-2)45) = 891
    11a+495n = -1089
    a+45n = -99

    If we are adding up the first 11 terms, then a = -144 and
    T28 = -144+27*45 = 1071
    T45 = -144+44*45 = 1836

    But, if we add up terms T5 through T15, then n=5, and a = -324 and
    T28 = 891
    T45 = 1656

    Better tie down your conditions a bit better

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    posted by Steve
  2. the sum of 11 terms of an a.p is 891 find the 28th and 45th terms if the common difference is 15

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  3. abcd is atrape zium in whibh ab 11 dc.\ab/=4 11cm.\dc/=9cm abc =68,\bb/=7.5cm calculate the area of the trapezium?

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