find the equation of the left half of the parabola: (x+5)^2=4y+2
(x+5)^2 = 4 (y + 1/2)
vertex at (-5, -1/2)
so for the left half x is always less than (to the left of) -5
an y is above -1/2
I do not know what else to say
vertex at (-5, -1/2)
so for the left half x is always less than (to the left of) -5
an y is above -1/2
I do not know what else to say