How many grams of HCl are needed in order to make 0.500 liters of a 0.100 M HCl solution?
1.82 g
18.2 g
0.500 g
In a liter you have .1 mol of HCl
.1 * (35.5 + 1) = 3.65 grams/liter
so in half a liter you have 1.825 grams of HCl
There is nothing wrong with Damon's response but I do these slightly differently. Chemistry thinks in mols. So we ask ourselves "How many mols do I need?" That's
mols = M x L = 0.1 x 0.500 = 0.05
Then mols = grams/molar mass
0.05 = g/36.5 and solve for g = 36.5 x 0.05 = 1.825. If your chem prof is picky about significant figures s/he will tell you that's too many and you should round that number to 1.82.
To calculate the number of grams of HCl needed, you need to use the formula:
moles = volume (L) × concentration (M)
First, convert the volume from liters to milliliters:
0.500 liters = 500 milliliters
Now, substitute the values into the formula:
moles = 500 mL × 0.100 M
Next, convert milliliters to liters:
moles = 0.500 L × 0.100 M
Finally, multiply the moles by the molar mass of HCl:
moles of HCl = 0.500 L × 0.100 M × 36.461 g/mol
Calculating this gives:
moles of HCl = 1.823 g
So, the correct answer is 1.82 g.
To calculate the grams of HCl needed to make a specific volume and concentration of a solution, you need to use the equation:
Grams of solute = Volume of solution * Concentration * Molar mass
In this case, the volume of the solution is given as 0.500 liters, and the concentration is given as 0.100 M (moles per liter). So, we need to determine the grams of HCl.
First, we need to convert the volume from liters to milliliters since the molar mass of HCl is commonly given in grams per milliliter.
0.500 liters * 1000 milliliters/liter = 500 milliliters
Next, we calculate the grams of HCl using the formula:
Grams of HCl = (Volume of solution in milliliters * Concentration * Molar mass) / 1000
Since the molar mass of HCl is approximately 36.47 g/mol, we can compute the grams of HCl:
Grams of HCl = (500 milliliters * 0.100 M * 36.47 g/mol) / 1000 = 1.8235 g
Therefore, the correct answer is 1.82 g (rounded to two decimal places).