# trig

A car drives 1000 feet on a road that is 8 degrees to the horizontal, as shown in the figure. The car weighs 3400 lb. Thus gravity acts straight down on the car with a constant force F=-3400j. Find the work done by the car in overcoming gravity?

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1. Work done
=F.D
=F*D*cos(θ)
=<0,-3400><1000sin(8°),1000cos(8°)>
=3400000cos(8°) ft-lb (gravitation units)

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posted by MathMate

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