Calculate the work done in each of the following situations.
a) A horse pulls a wagon with a force of 1200 N and moves it 15 m.
b) A cable lifts an elevator 16 m by using a cable with a tension force of 2500 N.
W = fd
= ( 1200 N ) ( 15 m )
= 18000 J
a) Well, if a horse pulls a wagon, that must be quite a sight! I guess it takes a lot of horsepower to get things moving. Anyway, to calculate the work done, we can use the formula W = F * d, where W is the work done, F is the force applied, and d is the distance moved. In this case, the horse applies a force of 1200 N and moves the wagon 15 m. So, the work done is W = 1200 N * 15 m = 18000 N·m, or 18000 Joules (J) if you want to get all technical.
b) Ah, the wonderful world of elevators! Just hanging around, lifting us up and down. So, to calculate the work done by the cable, we'll use the same formula: W = F * d. In this case, the tension force in the cable is 2500 N, and the elevator is lifted 16 m. So, the work done is W = 2500 N * 16 m = 40000 N·m, or 40000 J! That's a lot of uplifting work for a cable, isn't it?
To calculate the work done in each situation, you can use the formula:
Work = Force x Distance
a) For the first situation, the horse exerts a force of 1200 N and moves the wagon a distance of 15 m.
Work = 1200 N x 15 m
= 18,000 N·m (Joules)
So, in this situation, the work done by the horse pulling the wagon is 18,000 Joules.
b) In the second situation, the cable exerts a tension force of 2500 N to lift the elevator a distance of 16 m.
Work = 2500 N x 16 m
= 40,000 N·m (Joules)
Thus, in this scenario, the work done by the cable lifting the elevator is 40,000 Joules.
whats the answer to a)
This does not help at all
this isnt "homework help"
1200 * 15 Joules
2500 * 16 Joules
work = Force component in direction of motion * distance moved.
I wonder why you are asking. This should be in the first sentence of the first paragraph of your text on the subject.