# physics

Determine the final velocity of a medicine ball that is dropped from a height of 7.00 meters. (assume air resistance is negligible)

I don't understand how to solve this with only change in x. I imagine I am supposed to assume initial velocity is 0 m/s, but, even if that is assumed, I don't understand what I can do to find the final velocity.

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1. Yes, when an object is DROPPED, the
initial velocity is 0. When an object is
THROWN up or down, the initial velocity
is not 0.

V^2 = Vo^2 + 2g*h
V^2 = 0 + 19.6*7 = 137.2
V = 11.71 m/s.

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posted by Henry

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