A gas has a volume of 590 mL at a temperature of –55.0 C. What volume will the gas occupy at 30.0 C?

V1T1 = V2T2
(590 mL)(-55.0C) / (30.0C) = 1081.67 mL

273 + (-55) = 218 K

590/218 = V2/303
V2 = 590 (303/218) = 820 ml

Is my work and answer correct??

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asked by Angela
  1. I have trouble following what you've done. The first part where you end up with 1081.67 mL is not right for two reasons.
    1. The formula should be V1/T1 = V2/T2
    2. You didn't convert T to kelvin.

    The second calculation you did is correct.

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    posted by DrBob222

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