Physics

The length of a box is reduced to two third of its original value and the width and height are tripled. Calculate the factor by which the volume has changed.

Am I on the right track? If not please help I am stuck. Thanks.

V=LWH
V=(L-2/3)(3W)(3H)

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asked by Jane
  1. (2L/3)(3W)(3H)

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    posted by Damon

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