math logarithm
 👍 0
 👎 0
 👁 142

 👍 0
 👎 0
posted by MathMate
Respond to this Question
Similar Questions

Algebra 2
If log10^9=0.95 and log10^2=0.30, find the following: 1. log10^9/2 2. log10^3 3. log10^36 4. log10^20/9 5. log10^900 6. log10^1/9 7. log10^1/2000 8. log10^162 I need to see all of the steps. Thanks
asked by Brandon on May 12, 2011 
math
how can you simplify this?? log10(10^.5) log10 as in log base 10 By definition: Log_10[10^(x)] = x ok, but it is 10 to the 1/2 power, not x how would you simplify it then? That's then the special case of x = 1/2: If for all x:
asked by david on July 14, 2007 
Algebra 2
Express as a logarithm of a single number or expression: 1. 5log4^p+log4^q 2. log10^x4 log10^y 3. 4log3^A1/2 log3^B 4. log5^M+1/4 log5^N 5. log2^M+log2^N+3 6. log5^xlog5^y+2 7. 13 log5^x 8. (1+log9^x)/2 I need to see all of
asked by Brandon on May 12, 2011 
algebra 2
Use change of base to rewrite the expression, log5 16 When I solved this, I got log10 16 / log10 5 But when checking it on mathway I got log 16 / log 5 Could someone explain this?
asked by huncho jack on March 12, 2018 
Math
What is the logarithmic function modeled by the following table? x f(x) 8 3 16 4 32 5 f(x) = logx 2 f(x) = log2 x f(x) = 2 log10 x f(x) = x log10 2
asked by Please Help Me on October 8, 2014

Math
Simplify the logarithm. Log10 103
asked by Toria on December 14, 2013 
Logarithms
Using the approximation log10^2=0.301, find: log10^8
asked by Sam on October 14, 2012 
Pre Calculs
The pH of a chemical solution is given by the formula pH = log10 [H+] where [H+] is the concentration of hydrogen ions in moles per liter. Values of pH range from 0 (acidic) to 14 (alkaline). (a) what is the pH of the solution
asked by Erica on October 10, 2006 
phyiscs repost 2
Calculate the sound level in decibels of a sound wave that has an intensity of 2.25 µW/m2 For this question don't I use B=log10(I/IO) So it would be B=log10(2.25/1.0e12) right?
asked by chris adison on April 19, 2008 
Math
Simply 1 /2 log10 252 log10 3+ log10 18
asked by Anonymous on July 19, 2019