# Physics

A 15.0 kΩ resistor is hooked up to a 45.0 V battery in a circuit with a switch.

a.) What is the current flowing through the resistor?
b.) What is the power dissipated by the resistor?

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1. V=IR
I=V/R=45/15000=3*10-3 A.
Power = VI joules

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posted by MathMate
2. Power = VI watts

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posted by MathMate

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