college algebra

A rectangular garden is 20 ft longer than it is wide. Its area is 8000 ft{}^2. What are its dimensions?

Let "w" equal the width
w+20=8000
w^2+20=8000

not sure how to continue

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  1. If w = width, then length = w + 20

    w(w+20) = 8000

    Solve for w, then length.

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    posted by PsyDAG
  2. you have the right idea, but you should have said

    w(w+20) = 8000
    w^2+20w = 8000
    w^2+20w-8000 = 0
    (w-80)(w+100) = 0
    ...

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    posted by Steve
  3. How do I isolate w ?

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  4. so w=80 and w=-100 ?

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  5. If two numbers multiply to produce a product of zero, then one of them must be zero.

    So, if (w-80)(w+100)=0, then either

    w-80 = 0
    w=80

    or

    w+100 = 0
    w = -100

    Now pick the value that makes sense for this problem. Then check your conclusion by plugging in the value and seeing whether it produces a rectangle of the correct area.

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    posted by Steve

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