A triangular-shaped wall has a base of 2x=4 and a height of x+3. The area of the triangle is 56 squared inches. What is the value of x?
1/2 (2x+4)(x+3) = 56
x^2+5x-50 = 0
(x+10)(x-5) = 0
...
To find the value of x, we need to find the equation representing the area of the triangle.
The formula for the area of a triangle is:
Area = (1/2) * base * height
In this case, the base is 2x = 4 and the height is x + 3. We can substitute these values into the equation:
Area = (1/2) * (2x) * (x + 3)
Substituting the given area of 56 square inches:
56 = (1/2) * 4 * (x + 3)
Now, let's simplify and solve for x:
56 = 2(x + 3)
56 = 2x + 6
50 = 2x
x = 25
So, the value of x is 25.
To find the value of x, we can use the formula for the area of a triangle: Area = (1/2) * base * height.
Given:
Base = 2x = 4
Height = x + 3
Area = 56 square inches
We can substitute the given values into the area formula and solve for x.
Area = (1/2) * base * height
56 = (1/2) * 4 * (x + 3)
Now, let's simplify the equation.
56 = 2 * (x + 3)
56 = 2x + 6
Next, let's isolate the variable x by subtracting 6 from both sides of the equation.
56 - 6 = 2x
50 = 2x
Finally, we can solve for x by dividing both sides of the equation by 2.
50/2 = x
25 = x
Therefore, the value of x is 25.