Physics

A 1 kg hockey puck is sliding on the ice at 5m/s and stops on some dirt in 2 secs. I need to find the coefficient of kinetic friction.
I found the acceleration being -2.5m/s^s (0-5m/s / 2s)
Idk what to do next pleaseeee help

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asked by Lola
  1. Good, so
    Frictional force = ma = 1kg (-2.5)m/s²
    = -2.5 N

    Normal reaction
    =mg
    =1kg * 9.8 m/s²
    =9.8 N

    Coefficient of kinetic friction
    = Frictional force / Normal reaction
    = -2.5 / 9.8
    = 0.255 (omit sign).

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    posted by MathMate

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