physics

a wooden slab starting from rest slide down a 10m long inclined plane with acceleration of 5m per sec what would be the speed ay the bottom of the inclined plane

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  1. V^2 = Vo^2 + 2a*d
    V^2 = 0 + 10*10 = 100
    V = 10 m/s.

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    posted by Henry

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