physics

An 66.0 N box of clothes is pulled 5.5 m up a 30.0° ramp by a force of 116 N that points along the ramp. If the coefficient of kinetic friction between the box and the ramp is 0.22, calculate the change in the box's kinetic energy.

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  1. h = L*sin A = 5.5*sin30 = 2.75 m.

    Fn = mg*Cos A = 66*Cos 30 = 57.16 N. =
    Normal force = Force perpendicular to
    the ramp.

    Fk = u*Fn = 0.22 * 57.16 = 12.57 N. =
    Force of kinetic friction.

    KE + PE = mg*hmax-Fk*L
    KE + PE = 66*2.75-12.57*5.5 = 112.4 J.
    0 + PE = 112.4
    PE = 112.4 J. at bottom of ramp.

    KE + PE = 112.4 J. at top of ramp.
    KE + 0 = 112.4
    KE = 112.4 J.
    KE(change) = 112.4 - 0 = 112.4 J.

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    posted by Henry

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