algebra/check my answer

Three fair coins are tossed. What is the probability that at least one is a head? (Enter the probability as a fraction.) I came up with 7/8

Thank you

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  1. find probability that NONE are heads

    (1/2)^3 = 1/8
    so we want
    1 - 1/8 = 7/8 agree with you

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    posted by Damon

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