# Algebra 1

1. 3a^4b/2a^2c^3 ÷ 12a^2c/8c^4

A: ?

2. x^2 + 4x - 5/3x - 3 ÷ (xC^2 - 25)

A: ?

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3. 👁 72
1. when dividing by a fraction, just invert and multiply. So,

#1
3a^4b/2a^2c^3 * 8c^4/12a^2c
= 3*8/12 a^4/a^2 b c/c^3
...

#2
x^2+4x-5 = (x+5)(x-1)
x^2-25 = (x+5)(x-5)

So, you just have

(x+5)(x-1) / 3(x-1) * 1 / (x+5)(x-5)
= (x+5)(x-1) / 3(x+5)(x-1)(x-5)
= ...

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posted by Steve
2. 1. A: ?

2. A: 1/3x-15

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3. Am I correct?

I still don't know the answer to #1.

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2a^2b / c^2

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posted by Steve
5. Is this the answer to #1? Or am I incorrect?

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6. yes,
#1 = 2a^2b/c^2
#2 = 1/(3x-15)

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posted by Steve

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