# math

A rectangle has a perimeter of 23cm.
Its area is 33 cm*2. Determine the dimensions of the rectangle.

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1. 2L + 2W = 23
L= 11.5 - w
Area=33=l(w)
=(11.5-w)(w)
=11.5w - w*2
h=-11.5/2(1)
=5.75
L=11.5-5.75=5.75
Dimensions are 5.75m by 5.75m
So this would make it a square?

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posted by Lorrie
2. Is the answer I gave correct?

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posted by Lorrie
P=2x +2y=23
x+y=11.5
y=11.5-x
x(11.5-x)= 33
11.5x -x^2=33
(Multiply by 2 to get rid of decimal?)
23x-2x^2=66
23x-2x^2+66=0
(x-6)(2x-11)=0
Sub 6 into y= 11.5-x=11.5-6=5.5
Sub 5.5, 5.5=11.5-x, x=11.5-5.5=6
Therefore the dimensions of the rectangle are 6cm by 5.5cm. CORRECT?

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posted by Lorrie

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