math

A rectangle has a perimeter of 23cm.
Its area is 33 cm*2. Determine the dimensions of the rectangle.

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asked by Lorrie
  1. 2L + 2W = 23
    L= 11.5 - w
    Area=33=l(w)
    =(11.5-w)(w)
    =11.5w - w*2
    h=-11.5/2(1)
    =5.75
    L=11.5-5.75=5.75
    Dimensions are 5.75m by 5.75m
    So this would make it a square?

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    posted by Lorrie
  2. Is the answer I gave correct?

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    posted by Lorrie
  3. 2nd answer:
    P=2x +2y=23
    x+y=11.5
    y=11.5-x
    x(11.5-x)= 33
    11.5x -x^2=33
    (Multiply by 2 to get rid of decimal?)
    23x-2x^2=66
    23x-2x^2+66=0
    (x-6)(2x-11)=0
    Sub 6 into y= 11.5-x=11.5-6=5.5
    Sub 5.5, 5.5=11.5-x, x=11.5-5.5=6
    Therefore the dimensions of the rectangle are 6cm by 5.5cm. CORRECT?

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    posted by Lorrie

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