# Chemistry

Dr bob for this question :Calculate the molar solubility of manganese II hydroxide in ph 12.85 solution. The Ksp is 2.1 x 10^-13 but I can't solve for x thanks.

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1. Ksp = (Mn^2+)(OH^-)^2
2.1E-13 = (x)(2x + 0.07)^2
To avoid a quadratic assume 2x + 0.07 = 0.07
2.1E-13 = (x)(0.0708)^2
x = (2.1E-13/(0.0708)^2
etc.

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