A is a solution of HCL containing 7.30g/dm3.B is a solution ofX2CO3 containing 10.6g/dm3.assume that average volume of acid is 2.81cm3 and the volume of base is 25.00cm3.from your result and information .calculate (I)concentration of A in mol/dm3(ii)concentration of B in mol/dm3 (H-1.00 cl-35.5 O-16.00 C-12.0
A is a solution of HCI containing 7.30g /dm3. B is a solution of X2CO3 containing 10.6g/dm3. Put A into burette and titrate against 25 portions of B using methyl orange. Tabulated your burette readings and calculate the average volume of A used. The equation
for the reaction involved in the titration is X2CO3 +HCI - 2XCl +H2O +CO2
C from your result and information provided above, calculate the ; concentration of A in mole/dm3
Concentration of B in mole/dm3
Molar mass of X2CO3 (HCl +36.5g/dm3
2HCl + X2CO3 ==> H2O + CO2 + 2XCl
mols HCl = g/molar mass = 7.3/36.5 = ?
M HCl = mols/dm3 = about 0.2
In the titration,
mols HCl = 0.00281 x 0.2 = ?
mols X2CO3 = 1/2 that from the coefficients
M X2CO3 = mols X2CO3/25 = ?
To calculate the concentration of A in mol/dm^3, we need to convert the mass of A (in this case, HCl) to moles and divide it by the volume in dm^3.
I) Concentration of A (HCl) in mol/dm^3:
First, let's calculate the number of moles of HCl in the solution:
Number of moles = mass / molar mass
The molar mass of HCl is (1.00 H + 35.5 Cl) = 36.5 g/mol.
Number of moles of HCl = 7.30 g / 36.5 g/mol = 0.2 moles
Now, we need to convert the volume from cm^3 to dm^3:
Volume of solution (A) = 2.81 cm^3 = 2.81 / 1000 dm^3 = 0.00281 dm^3
Concentration of A (HCl) = Number of moles / Volume of solution (A)
Concentration of A (HCl) = 0.2 moles / 0.00281 dm^3 ≈ 71.17 mol/dm^3
Therefore, the concentration of A (HCl) is approximately 71.17 mol/dm^3.
II) Concentration of B (X2CO3) in mol/dm^3:
Similarly, to calculate the concentration of B (X2CO3) in mol/dm^3, we follow the same steps:
Number of moles of X2CO3 = mass / molar mass
The molar mass of X2CO3 is (2X + 1.00 C + 3*16.00 O) = (2*12.0 + 1.00*12.0 + 3*16.00) = 106.0 g/mol
Number of moles of X2CO3 = 10.6 g / 106.0 g/mol = 0.1 moles
Volume of solution (B) = 25.00 cm^3 = 25.00 / 1000 dm^3 = 0.025 dm^3
Concentration of B (X2CO3) = Number of moles / Volume of solution (B)
Concentration of B (X2CO3) = 0.1 moles / 0.025 dm^3 = 4.0 mol/dm^3
Therefore, the concentration of B (X2CO3) is 4.0 mol/dm^3.
To calculate the concentration of solution A (HCl) and solution B (X2CO3) in mol/dm3, we need to convert the given masses of the solute into moles and then divide by the volume of the solution in dm3.
Let's start with solution A (HCl):
Step 1: Calculate the moles of HCl (A)
To convert the mass of HCl to moles, we need to use the molar mass of HCl, which is the sum of the atomic weights of hydrogen (H) and chlorine (Cl):
Molar mass of HCl = (1.00 g/mol x 1) + (35.5 g/mol x 1) = 36.5 g/mol
Moles of HCl = mass of HCl / molar mass of HCl
Moles of HCl = 7.30 g / 36.5 g/mol = 0.20 mol
Step 2: Calculate the concentration of HCl (A)
Concentration of HCl (A) = moles of HCl / volume of solution A
Convert the volume of solution A from cm3 to dm3:
Volume of solution A = 2.81 cm3 = 2.81 cm3 * (1 dm3 / 1000 cm3) = 0.00281 dm3
Concentration of HCl (A) = 0.20 mol / 0.00281 dm3 = 71.17 mol/dm3
Therefore, the concentration of solution A (HCl) is 71.17 mol/dm3.
Now, let's move on to solution B (X2CO3):
Step 1: Calculate the moles of X2CO3 (B)
To convert the mass of X2CO3 to moles, we need to use the molar mass of X2CO3, which is the sum of the atomic weights of carbon (C) and oxygen (O):
Molar mass of X2CO3 = (12.0 g/mol x 1) + (16.00 g/mol x 3) = 44.0 g/mol
Moles of X2CO3 = mass of X2CO3 / molar mass of X2CO3
Moles of X2CO3 = 10.6 g / 44.0 g/mol = 0.24 mol
Step 2: Calculate the concentration of X2CO3 (B)
Concentration of X2CO3 (B) = moles of X2CO3 / volume of solution B
Volume of solution B = 25.00 cm3 = 25.00 cm3 * (1 dm3 / 1000 cm3) = 0.025 dm3
Concentration of X2CO3 (B) = 0.24 mol / 0.025 dm3 = 9.6 mol/dm3
Therefore, the concentration of solution B (X2CO3) is 9.6 mol/dm3.
To summarize:
(i) The concentration of solution A (HCl) is 71.17 mol/dm3.
(ii) The concentration of solution B (X2CO3) is 9.6 mol/dm3.