Math

An ordinary (fair) die is a cube with the numbers
1
through
6
on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment.

Compute the probability of each of the following events:
Event
A
: The sum is greater than
5
.
Event
B
: The sum is divisible by
5
.

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  1. Answer

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  2. die a-> 1 2 3 4 5 6
    die b
    1
    2
    3
    4
    5
    6

    36 boxes
    label them for the sum of number above and to the left
    eg
    2 3 4 5 ....7
    3 4 5 7 ....8
    4 5 ........9
    etc
    Now for example 6 of the boxes contains a sum less than 5
    that means 30/36 are greater than five
    of course 30/36 = 5/6

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    posted by Damon

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