# Math

An ordinary (fair) die is a cube with the numbers
1
through
6
on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment.

Compute the probability of each of the following events:
Event
A
: The sum is greater than
5
.
Event
B
: The sum is divisible by
5
.

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2. 👎 0
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1. Answer

1. 👍 0
2. 👎 0
2. die a-> 1 2 3 4 5 6
die b
1
2
3
4
5
6

36 boxes
label them for the sum of number above and to the left
eg
2 3 4 5 ....7
3 4 5 7 ....8
4 5 ........9
etc
Now for example 6 of the boxes contains a sum less than 5
that means 30/36 are greater than five
of course 30/36 = 5/6

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posted by Damon

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