Algebra 1--Please, help me!

The side of a trinagular roof is to have the same height h and base b^2 as the side of a trapezodial roof.

a. What is the ratio of the area of the triangular roof to the area of the trapezoidal roof?

(For a triangle, A = 1/2b^2h. For a trapezoid, A = b1 + b2/2h.)

b. Compare the ratio from part of question a to what the ratio will be if b1 is doubled for trapezoidal roof and b2 is doubled for both roofs.

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  1. (a) want a ratio? Just plug in the numbers for a fraction

    (1/2 b^2 h) / ((b1+b2)/2 h)
    = b^2/(b1+b2)

    For (b), just substitute in new values and see how the ratio changes.

    By the way, having b^2 for one figure and b1+b2 for the other plays havoc with the units. Better check your problem again.

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    posted by Steve

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