find the equation of the perpendicular bisector of the line joining P(2, -4) to Q(-5,1)
A. 8y-14x 13=0
B. 8y-14x-13=0
C. 8y 14x-13=0
D. 8y 14x 13=0
Please I need someone to help me with this, with an explanatory workings.

asked by Francis
  1. the bisector goes through the midpoint of PQ. That is (-3/2,-3/2)

    PQ has slope -5/7, so the perpendicular has slope 7/5

    Now you have a point and a slope, so the line is

    y+3/2 = 7/5 (x+3/2)
    10y + 15 = 14x + 21
    10y-14x-6 = 0

    I suspect a typo. If you graph the two lines, you will see that PQ is indeed bisected by the calculated line.

    posted by Steve
  2. So the question is wrong?

    posted by Francis
  3. Yes. P and Q cannot be as given.
    All of the choices have slope 7/4 or -7/4.

    posted by Steve
  4. ok, can you pls direct me on how to work a similar question?

    posted by Francis
  5. Uh, geez -- I believe I just did. Given two points, find the midpoint of the line connecting them.

    Find the slope of that line, and take its negative reciprocal.

    Now you have a point and a slope. Just write the equation of the bisecting line.

    posted by Steve
  6. Alright, thanks.

    posted by Francis
  7. Sorry one more thing, how do you get the slope?

    posted by Francis

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