if a train travell at speed of 90km/hour. and when the break applied at 5m/sec2. how much it will travel before stoping
90 km/hour = 90/3.6=25 m/s
deceleration rate, a = 5 m/s²
time= 25/5
= 5 seconds
Must be a new braking system :)
deceleration rate, a = 5 m/s²
time= 25/5
= 5 seconds
Must be a new braking system :)