# Maths Probability

Consider a Markov chain X0,X1,X2,… described by the transition probability graph shown below. The chain starts at state 1; that is, X0=1.

Find the probability that X2=3.

Find the probability that the process is in state 3 immediately after the second change of state. (A “change of state" is a transition that is not a self-transition.)

Find (approximately) P(X1000=2∣X1000=X1001).

Let T be the first time that the state is equal to 3.

Suppose for this part of the problem that the process starts instead at state 2, i.e., X0=2. Let S be the first time by which both states 1 and 3 have been visited.

E[S]

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1. I am in need of the above soln if anybody knew solution please give answers...

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2. you did not provide transition probability graph/matrix when you first posted the problem

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3. I posted the matrix in my post. I also posted the answers I got wrong when I tried.

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4. I am not sure and I cannot check it until i am sure but for 1 I have 3/32 or 1/4 * 3/8.
for 2 I have 1/2 but really not sure
3 could be 1/3
4 should be 20/3 which the sum of 1/1/p of 1/4 + 3/8
5 ???

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6. I only have one answer left.

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7. @gugget
Only (2) is correct
which is = 1/2

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8. 1)3/32 correct
2)0.5 correct
3)1/3 incorrect
4)20/3 incorrect
5

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9. Thanks

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