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calc
derivative of (x^3/6)+(1/2x)? i got (x^2/2)(1/2x^2) is that correct? and then wut is the (F'(x))2?...meaning the derivative squred? if you meant (1/2)x^2  1/(2x^2) you are correct I don't think they are looking for the square of
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R=M^2(c/2m/3) dR/dM=CMM^2 I found the derivative. Now how would I find the vale of M that maximize the derivative dR/dM? set it to zero, and solve for m. You get two solutions. Use the second derivative to see which one is the
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How do you get m=0? from taking the second derivative? does c=1? Can you check my work on how I get the derivative of R=M^2(c/2m/3) NEXT R=1/2(CM^2)1/3(M^3) NEXT dR/dM=CMM^2. I checked in the back, and that was the answer for
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