An 8.5 m extension ladder of mass 24 kg is propped up against a wall, touching at a point 8.0 m above the level ground. A man of mass 75 kg climbs 2.0 m up the ladder to repair a window. The ladder rests against a frictionless wall, but the ground has friction. Determine the magnitude and direction of all forces on the ladder.

Normal force exerted by the ground.

Frictional force exerted by ground.

Force exerted by wall.

Force exerted by man.

Force exerted by weight of ladder.

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1. a) 24kg * 9.8m/s^2 + 75kg * 9.8m/s^2 = 970N

b) A = sqrt[(8.5m)^2 - (8m)^2] = 2.87m
CC = 2m
CC / AC = 2m/B = 8m / 2.87m
AC= 2m * 2.87 / 8m
AC = 0.7175m

BA = 8.5m / 2m = 4.25m

AC / BA = AO / AD
AC / 4.25m = 2.87m / 8.5m
AC2 = 2.87m * 4.25m / 8.5m
AC2 = 1.435m

F2AC1 + F1AC2 - Ff * 8m = 0
Ff = 75kg * 9.8m/s^2 * 2.5m + 24kg * 9.8m/s^2 * 0.41m / 8m
Ff = (735N * 0.7175m + 235.2N * 1.435m) / 8m
Ff = 104N

c) Force exerted by wall = Frictional force exerted by ground.
Force by wall = 104NN

d) Force of man = 75kg * 9.8m/s^2 = 735N

e) Force of ladder = 24kg * 9.8m/s^2 = 235N

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