# Intermediate algebra

Seven times the difference of six and a twice a number yields the same result as the same number decreased by one.

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3. 6
1. 7(6-2x) = x -1
42 - 14 x = x -1
15 x = 43
x = 43/15

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posted by drwls
2. 7(6-2n)=n-1

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posted by Anonymous
3. Combine like terms:
-3x2 + 2x – 4x2 – 9 + 6x – 2x2 + 8

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posted by Anonymous
4. Solve for x:
-2(x – 5) + 7 = x – 8 – 5x

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posted by happy
5. Solve for x:
(x – 2)/5 – 3/2 = (x + 1)/10

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posted by happy
6. How do you Solve for x:
(x – 2)/5 – 3/2 = (x + 1)/10

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posted by Leon Connell
7. The difference of a number and 9 is the same as 45 decreased by that same number.

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posted by Jean

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