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In a triangle PQR. Q=8cm , R=6cm . Cosp=1/12.calculatethe value of p

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  1. I think you mean:
    In a triangle PQR. q=8cm , r=6cm . Cos(P)=1/12. Calculate the value of p.

    where capital letters mean vertices, lower-case letters mean lengths of sides opposite the corresponding vertex.

    Use cosine rule:
    p²=q²+r²-2qr(cos(P))
    and solve for p.

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