# Trig 2

What is the smallest value for x where y = sin 2x reaches its maximum ...wtf that means.

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1. sin(2x) is always between -1 and 1.
Since sin(pi/2) is the first time that it reaches 1,
sin(2x)=1 when 2x = pi/2
That is, when x = pi/4

If you don't know wtf, just take a look at the graph and see where it reaches its maximum.

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posted by Steve
2. What graph ...?

i appreciate the help but I can't see it ...

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posted by Joe
3. Hmmm. I think what we have here is a failure to communicate...

The graph of sin(2x) is here. You can plainly see that it reaches its maximum at x = pi/4.

http://www.wolframalpha.com/input/?i=sin%282x%29

Not sure what quadratic you are referring to. If you instead meant sin^2(x), then that is a max at x = pi/2, since sin(pi/2) = 1. Now, sin(3pi/2) is -1, so sin^2(x) is also 1 there, but pi/2 comes first.

http://www.wolframalpha.com/input/?i=sin^2%28x%29

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posted by Steve
4. I just meant a 4 quad graph ...x and y intersecting like you have in the link.

OK, this part is a trig rule?
sin(2x) is always between -1 and 1.

Because it covers 2 integers? One on either side of 0 (origin?)On the x axis?

In this equation, they show no graph.
If that matters. How would i know that the graph runs in units of .5p (x axis) or .5p up and down the y axis?

Looking at the graph, I see where sin(pi/2) = 1.

I can see here that you are dividing each side by 2 and that's how we end up with p/4.

Can you put it in a proper equation form? I know this is tedious and ultra simplistic for you Steve, but for me it's like trying to read Egyptian hieroglyphics.

You can't imagine how much I want to understand this.
Thanks again.

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posted by Joe
5. Steve, let's take this up a notch.

My number is 800 828 2950

I'll send you my email?

You are in the U.S. i take it?

I'm here in Lorain county OH.

i can send you a joinme link then you can see inside my pc while we talk on the phone together ...?
We can do some equations in real time with audio guidance ....?

let's do some equations together in real time while on our headsets together?

email is joseph
@SmartHealthInsuranceDOTcom

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posted by Joe
6. hi guys XD

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