Algebra 1 Answer Evaluation

Write each equation in standard form. Solve by using the Quadratic Formula.

1. -7 = x^2

A: ?

2. x^2 - 16 = 0

A: x = 4 or x = -4.

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  1. anything squared cannot be negative in the real number set, so your first one has no real number solution

    2. correct

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    posted by Reiny
  2. x^2 + 0 x + 7 = 0

    x = [ 0 +/- sqrt(-28) ]/2

    x = +/- 2 sqrt -7/2

    x = +/- sqrt(-7) or +/- i sqrt 7
    =================================

    x^2 - 0 x -16 = 0

    x = [ 0 + /- sqrt (0 +4*16) ]/2

    x = +/- 2*4/2

    x = +/- 4
    what else is new :)

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    posted by Damon
  3. Are you sure? I haven't written the equation in standard form yet.

    1. x^2 + 0x + 7 = 0

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  4. Yes, the only solutions to the first problem are the imaginary numbers +/- i sqrt 7
    where i is the sqrt of NEGATVE one

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    posted by Damon

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