Write each equation in standard form. Solve by using the Quadratic Formula.

1. -7 = x^2

A: ?

2. x^2 - 16 = 0

A: x = 4 or x = -4.

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1. anything squared cannot be negative in the real number set, so your first one has no real number solution

2. correct

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posted by Reiny
2. x^2 + 0 x + 7 = 0

x = [ 0 +/- sqrt(-28) ]/2

x = +/- 2 sqrt -7/2

x = +/- sqrt(-7) or +/- i sqrt 7
=================================

x^2 - 0 x -16 = 0

x = [ 0 + /- sqrt (0 +4*16) ]/2

x = +/- 2*4/2

x = +/- 4
what else is new :)

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posted by Damon
3. Are you sure? I haven't written the equation in standard form yet.

1. x^2 + 0x + 7 = 0

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4. Yes, the only solutions to the first problem are the imaginary numbers +/- i sqrt 7
where i is the sqrt of NEGATVE one

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posted by Damon

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