Math (Calculus)

Find the volume of the solid generated by revolving the region bounded by the graphs of the equations about the y-axis. (Use Disc Method)

y=3(2-x), y=0, x=0

asked by Sherman
  1. y-intercept is 6

    y = 6-3x
    3x = -y + 6
    x = -y/3 + 2
    x^2= y^2/9 - 4y/3 + 4

    vol = π[integral] y^2/9 - 4y/3 + 4 dy from 0 to 6
    = π[ y^3/27 - 2y^2/3 + 4y] from 0 to 6
    = π( 8 - 24 + 24 - (0) )
    = 8π

    better check my arithmetic

    posted by Reiny

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